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Bohr model energy levels: Class 12 practice

In the Bohr model of hydrogen, Eₙ = −13.6/n² eV and rₙ = 0.529n² Å. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Fractions

The idea behind bohr model energy levels

In the Bohr model of hydrogen, Eₙ = −13.6/n² eV and rₙ = 0.529n² Å. A jump from n₂ to n₁ emits a photon of energy E = 13.6(1/n₁² − 1/n₂²) eV and wavelength λ = 1240/E nm.

Step-by-step method

  1. Eₙ = −13.6/n².
  2. Photon energy = difference between levels.
  3. λ (nm) = 1240/E (eV).

Worked example 1 (Basic)

Find the energy and radius of the n = 2 orbit of hydrogen.

  1. Eₙ = −13.6/4 = -3.4 eV
  2. rₙ = 0.529 × 4 = 2.116 Å
  3. Answer: -3.4 eV, 2.116 Å

Worked example 2 (Standard)

Find the energy of the photon emitted when hydrogen's electron falls from n = 5 to n = 3.

  1. E = 13.6(1/9 − 1/25)
  2. = 0.967 eV
  3. Answer: 0.967 eV

Worked example 3 (Challenge)

Find the ionisation energy of hydrogen from the n = 4 level.

  1. E = 0 − (−13.6/16)
  2. = 0.85 eV
  3. Answer: 0.85 eV

Common mistakes and misconceptions

  • Sign errors with negative energies
  • Using n instead of n²

Practice questions

  1. (Basic) Find the energy and radius of the n = 5 orbit of hydrogen.
  2. (Basic) Find the energy and radius of the n = 3 orbit of hydrogen.
  3. (Standard) Find the energy of the photon emitted when hydrogen's electron falls from n = 4 to n = 2.
  4. (Standard) Find the energy of the photon emitted when hydrogen's electron falls from n = 3 to n = 1.
  5. (Challenge) Find the ionisation energy of hydrogen from the n = 6 level.
  6. (Challenge) Find the ionisation energy of hydrogen from the n = 3 level.

Answer key with full working

  • Q1: Eₙ = −13.6/25 = -0.544 eV → rₙ = 0.529 × 25 = 13.225 Å → Answer: -0.544 eV, 13.225 Å
  • Q2: Eₙ = −13.6/9 = -1.511 eV → rₙ = 0.529 × 9 = 4.761 Å → Answer: -1.511 eV, 4.761 Å
  • Q3: E = 13.6(1/4 − 1/16) → = 2.55 eV → Answer: 2.55 eV
  • Q4: E = 13.6(1/1 − 1/9) → = 12.089 eV → Answer: 12.089 eV
  • Q5: E = 0 − (−13.6/36) → = 0.378 eV → Answer: 0.378 eV
  • Q6: E = 0 − (−13.6/9) → = 1.511 eV → Answer: 1.511 eV

Syllabus note

This skill is listed under "Atoms" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is bohr model energy levels in?

"Atoms", Class 12 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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