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Polarisation: Brewster's law and Malus's law: Class 12 practice

Reflected light is completely polarised at Brewster's angle, where tan θ_B = n. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Trigonometry

The idea behind polarisation: brewster's law and malus's law

Reflected light is completely polarised at Brewster's angle, where tan θ_B = n. Through two polarisers at angle θ, transmitted intensity I = I₀cos²θ (Malus's law); unpolarised light is halved by the first polariser.

Step-by-step method

  1. For Brewster: θ_B = tan⁻¹ n.
  2. For Malus: I = I₀ cos²θ.
  3. Halve unpolarised light at the first polariser.

Worked example 1 (Basic)

Find Brewster's angle for glass of refractive index 1.33.

  1. θ_B = tan⁻¹(1.33)
  2. Answer: 53.06°

Worked example 2 (Standard)

Polarised light of intensity 17 W/m² passes a polariser at 45° to its plane. Find the transmitted intensity.

  1. I = 17 cos²45°
  2. Answer: 8.5 W/m²

Worked example 3 (Challenge)

Unpolarised light (84 W/m²) passes two polarisers with axes at 60°. Find the final intensity.

  1. After first: 42
  2. After second: 42 cos²60°
  3. Answer: 10.5 W/m²

Common mistakes and misconceptions

  • Using cos θ instead of cos²θ
  • Forgetting the first halving

Practice questions

  1. (Basic) Find Brewster's angle for glass of refractive index 1.6.
  2. (Basic) Find Brewster's angle for glass of refractive index 1.5.
  3. (Standard) Polarised light of intensity 49 W/m² passes a polariser at 60° to its plane. Find the transmitted intensity.
  4. (Standard) Polarised light of intensity 86 W/m² passes a polariser at 53° to its plane. Find the transmitted intensity.
  5. (Challenge) Unpolarised light (17 W/m²) passes two polarisers with axes at 37°. Find the final intensity.
  6. (Challenge) Unpolarised light (80 W/m²) passes two polarisers with axes at 30°. Find the final intensity.

Answer key with full working

  • Q1: θ_B = tan⁻¹(1.6) → Answer: 57.99°
  • Q2: θ_B = tan⁻¹(1.5) → Answer: 56.31°
  • Q3: I = 49 cos²60° → Answer: 12.25 W/m²
  • Q4: I = 86 cos²53° → Answer: 31.15 W/m²
  • Q5: After first: 8.5 → After second: 8.5 cos²37° → Answer: 5.42 W/m²
  • Q6: After first: 40 → After second: 40 cos²30° → Answer: 30 W/m²

Syllabus note

This skill is listed under "Wave Optics" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is polarisation: brewster's law and malus's law in?

"Wave Optics", Class 12 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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