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Doppler effect for sound: Class 11 practice

When a source moves towards a still listener, the observed frequency rises: f′ = f·v/(v − vₛ); moving away, f′ = f·v/(v + vₛ). Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Wave speed

The idea behind doppler effect for sound

When a source moves towards a still listener, the observed frequency rises: f′ = f·v/(v − vₛ); moving away, f′ = f·v/(v + vₛ). For a moving listener and still source, f′ = f(v ± vₒ)/v.

Step-by-step method

  1. Decide who moves and in which direction.
  2. Choose the sign that raises f when approaching.
  3. Substitute v (≈ 340 m/s).

Worked example 1 (Basic)

A 900 Hz siren approaches a still listener at 44 m/s (v = 340 m/s). What frequency is heard?

  1. f′ = 900 × 340/(340 − 44)
  2. Answer: 1033.78 Hz

Worked example 2 (Standard)

A 400 Hz source moves away from a still listener at 41 m/s. What frequency is heard?

  1. f′ = 400 × 340/(340 + 41)
  2. Answer: 356.96 Hz

Worked example 3 (Challenge)

A listener runs at 29 m/s towards a still 1200 Hz source. What frequency is heard?

  1. f′ = 1200 × (340 + 29)/340
  2. Answer: 1302.35 Hz

Common mistakes and misconceptions

  • Wrong sign
  • Using the formula for a moving listener when the source moves

Practice questions

  1. (Basic) A 1200 Hz siren approaches a still listener at 36 m/s (v = 340 m/s). What frequency is heard?
  2. (Basic) A 900 Hz siren approaches a still listener at 29 m/s (v = 340 m/s). What frequency is heard?
  3. (Standard) A 300 Hz source moves away from a still listener at 24 m/s. What frequency is heard?
  4. (Standard) A 1100 Hz source moves away from a still listener at 41 m/s. What frequency is heard?
  5. (Challenge) A listener runs at 29 m/s towards a still 1000 Hz source. What frequency is heard?
  6. (Challenge) A listener runs at 15 m/s towards a still 600 Hz source. What frequency is heard?

Answer key with full working

  • Q1: f′ = 1200 × 340/(340 − 36) → Answer: 1342.11 Hz
  • Q2: f′ = 900 × 340/(340 − 29) → Answer: 983.92 Hz
  • Q3: f′ = 300 × 340/(340 + 24) → Answer: 280.22 Hz
  • Q4: f′ = 1100 × 340/(340 + 41) → Answer: 981.63 Hz
  • Q5: f′ = 1000 × (340 + 29)/340 → Answer: 1085.29 Hz
  • Q6: f′ = 600 × (340 + 15)/340 → Answer: 626.47 Hz

Syllabus note

This skill is listed under "Waves" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is doppler effect for sound in?

"Waves", Class 11 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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