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Ellipse: foci and eccentricity: Class 11 practice

For x²/a² + y²/b² = 1 with a > b, c² = a² − b², foci (±c, 0) and eccentricity e = c/a (between 0 and 1). Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Squares and roots

The idea behind ellipse: foci and eccentricity

For x²/a² + y²/b² = 1 with a > b, c² = a² − b², foci (±c, 0) and eccentricity e = c/a (between 0 and 1). The major axis is 2a and the latus rectum 2b²/a.

Step-by-step method

  1. Identify a² (larger) and b².
  2. c = √(a² − b²).
  3. e = c/a; foci (±c, 0).

Worked example 1 (Basic)

For x²/100 + y²/36 = 1, find the foci and eccentricity.

  1. c² = 100 − 36 = 64, c = 8
  2. Foci (±8, 0)
  3. e = 4/5
  4. Answer: Foci (±8, 0), e = 4/5

Worked example 2 (Standard)

For x²/169 + y²/25 = 1, find the foci and eccentricity.

  1. c² = 169 − 25 = 144, c = 12
  2. Foci (±12, 0)
  3. e = 12/13
  4. Answer: Foci (±12, 0), e = 12/13

Worked example 3 (Challenge)

Find the length of the latus rectum of x²/100 + y²/64 = 1.

  1. 2b²/a = 2 × 64/10
  2. = 64/5
  3. Answer: 64/5

Common mistakes and misconceptions

  • Using c² = a² + b²
  • Taking a as the smaller value

Practice questions

  1. (Basic) For x²/25 + y²/9 = 1, find the foci and eccentricity.
  2. (Basic) For x²/25 + y²/16 = 1, find the foci and eccentricity.
  3. (Standard) For x²/289 + y²/225 = 1, find the foci and eccentricity.
  4. (Standard) For x²/169 + y²/144 = 1, find the foci and eccentricity.
  5. (Challenge) Find the length of the latus rectum of x²/289 + y²/225 = 1.
  6. (Challenge) Find the length of the latus rectum of x²/25 + y²/9 = 1.

Answer key with full working

  • Q1: c² = 25 − 9 = 16, c = 4 → Foci (±4, 0) → e = 4/5 → Answer: Foci (±4, 0), e = 4/5
  • Q2: c² = 25 − 16 = 9, c = 3 → Foci (±3, 0) → e = 3/5 → Answer: Foci (±3, 0), e = 3/5
  • Q3: c² = 289 − 225 = 64, c = 8 → Foci (±8, 0) → e = 8/17 → Answer: Foci (±8, 0), e = 8/17
  • Q4: c² = 169 − 144 = 25, c = 5 → Foci (±5, 0) → e = 5/13 → Answer: Foci (±5, 0), e = 5/13
  • Q5: 2b²/a = 2 × 225/17 → = 450/17 → Answer: 450/17
  • Q6: 2b²/a = 2 × 9/5 → = 18/5 → Answer: 18/5

Syllabus note

This skill is listed under "Conic Sections" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is ellipse: foci and eccentricity in?

"Conic Sections", Class 11 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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