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Finding the equation of a line: Class 11 practice

A line is fixed by a point and a slope (y − y₁ = m(x − x₁)) or by two points (slope first). Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Slope
  • Linear equations

The idea behind finding the equation of a line

A line is fixed by a point and a slope (y − y₁ = m(x − x₁)) or by two points (slope first). Parallel lines share a slope; perpendicular slopes multiply to −1.

Step-by-step method

  1. Find the slope.
  2. Use point-slope form.
  3. Rearrange to ax + by + c = 0 and check with a point.

Worked example 1 (Basic)

Find the equation of the line through (-1, 3) with slope 3.

  1. y − 3 = 3(x − -1)
  2. y = 3x + 6
  3. Answer: y = 3x + 6

Worked example 2 (Standard)

Find the equation of the line through (0, 1) and (1, 4).

  1. m = (4 − 1)/(1 − 0) = 3
  2. y = 3x + 1
  3. Answer: y = 3x + 1

Worked example 3 (Challenge)

Find the line through (-3, -2) perpendicular to y = 2x + 1. Write it as x + 2y = c.

  1. Perpendicular slope = −1/2
  2. y − -2 = −(1/2)(x − -3) → x + 2y = -7
  3. Answer: x + 2y = -7

Common mistakes and misconceptions

  • Using the same slope for perpendicular lines
  • Sign errors when rearranging

Practice questions

  1. (Basic) Find the equation of the line through (5, -1) with slope -3.
  2. (Basic) Find the equation of the line through (2, -1) with slope -2.
  3. (Standard) Find the equation of the line through (1, 1) and (2, 3).
  4. (Standard) Find the equation of the line through (1, 4) and (3, 10).
  5. (Challenge) Find the line through (-5, 2) perpendicular to y = 2x + 1. Write it as x + 2y = c.
  6. (Challenge) Find the line through (-4, 2) perpendicular to y = -4x + 1. Write it as x + -4y = c.

Answer key with full working

  • Q1: y − -1 = -3(x − 5) → y = -3x + 14 → Answer: y = -3x + 14
  • Q2: y − -1 = -2(x − 2) → y = -2x + 3 → Answer: y = -2x + 3
  • Q3: m = (3 − 1)/(2 − 1) = 2 → y = 2x − 1 → Answer: y = 2x − 1
  • Q4: m = (10 − 4)/(3 − 1) = 3 → y = 3x + 1 → Answer: y = 3x + 1
  • Q5: Perpendicular slope = −1/2 → y − 2 = −(1/2)(x − -5) → x + 2y = -1 → Answer: x + 2y = -1
  • Q6: Perpendicular slope = −1/-4 → y − 2 = −(1/-4)(x − -4) → x + -4y = -12 → Answer: x + -4y = -12

Syllabus note

This skill is listed under "Straight Lines" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is finding the equation of a line in?

"Straight Lines", Class 11 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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