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First-order reactions and half-life: Class 12 practice

For a first-order reaction k = (2.303/t) log([A]₀/[A]) and t½ = 0.693/k, independent of starting concentration. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Logarithms

The idea behind first-order reactions and half-life

For a first-order reaction k = (2.303/t) log([A]₀/[A]) and t½ = 0.693/k, independent of starting concentration. After n half-lives (1/2)ⁿ remains.

Step-by-step method

  1. Find k from data or from t½.
  2. Use k = (2.303/t) log([A]₀/[A]).
  3. t½ = 0.693/k.

Worked example 1 (Basic)

A first-order reaction has k = 0.0693 min⁻¹. Find its half-life.

  1. t½ = 0.693/0.0693
  2. = 10 min
  3. Answer: 10 min

Worked example 2 (Standard)

For k = 0.0231 min⁻¹, how long until 50% of the reactant has reacted?

  1. t = (2.303/0.0231) log(100/50)
  2. = 30.01 min
  3. Answer: 30.01 min

Worked example 3 (Challenge)

A first-order reaction has t½ = 35 s. What fraction remains after 140 s?

  1. n = 4 half-lives
  2. (1/2)^4 = 1/16
  3. Answer: 1/16

Common mistakes and misconceptions

  • Using the zero-order formula
  • log vs ln confusion

Practice questions

  1. (Basic) A first-order reaction has k = 0.0231 min⁻¹. Find its half-life.
  2. (Basic) A first-order reaction has k = 0.00693 min⁻¹. Find its half-life.
  3. (Standard) For k = 0.0693 min⁻¹, how long until 90% of the reactant has reacted?
  4. (Standard) For k = 0.00693 min⁻¹, how long until 99% of the reactant has reacted?
  5. (Challenge) A first-order reaction has t½ = 10 s. What fraction remains after 40 s?
  6. (Challenge) A first-order reaction has t½ = 53 s. What fraction remains after 265 s?

Answer key with full working

  • Q1: t½ = 0.693/0.0231 → = 30 min → Answer: 30 min
  • Q2: t½ = 0.693/0.00693 → = 100 min → Answer: 100 min
  • Q3: t = (2.303/0.0693) log(100/10) → = 33.23 min → Answer: 33.23 min
  • Q4: t = (2.303/0.00693) log(100/1) → = 664.65 min → Answer: 664.65 min
  • Q5: n = 4 half-lives → (1/2)^4 = 1/16 → Answer: 1/16
  • Q6: n = 5 half-lives → (1/2)^5 = 1/32 → Answer: 1/32

Syllabus note

This skill is listed under "Chemical Kinetics" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is first-order reactions and half-life in?

"Chemical Kinetics", Class 12 Chemistry (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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