RG's E-Learning Centre · Book a free demo class · WhatsApp +91-9379416374

RMS speed of gas molecules: Class 11 practice

v_rms = √(3RT/M) with M in kg/mol and T in kelvin. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Square roots

The idea behind rms speed of gas molecules

v_rms = √(3RT/M) with M in kg/mol and T in kelvin. Average kinetic energy per molecule = (3/2)kT. Doubling absolute temperature raises v_rms by √2.

Step-by-step method

  1. Convert M to kg/mol and T to K.
  2. v_rms = √(3RT/M).
  3. For ratios use v ∝ √(T/M).

Worked example 1 (Basic)

Find the rms speed of N₂ molecules at 461 K.

  1. v = √(3 × 8.314 × 461 / 0.028)
  2. = 640.82 m/s
  3. Answer: 640.82 m/s

Worked example 2 (Standard)

Find the average kinetic energy of a gas molecule at 599 K.

  1. KE = (3/2)kT = 1.5 × 1.38 × 10⁻²³ × 599
  2. = 1.240e-20 J
  3. Answer: 1.240e-20 J

Worked example 3 (Challenge)

By what factor does the rms speed change if the absolute temperature becomes 9 times?

  1. v ∝ √T
  2. √9 = 3
  3. Answer: 3 times

Common mistakes and misconceptions

  • Using g/mol
  • Using °C

Practice questions

  1. (Basic) Find the rms speed of H₂ molecules at 506 K.
  2. (Basic) Find the rms speed of CO₂ molecules at 323 K.
  3. (Standard) Find the average kinetic energy of a gas molecule at 267 K.
  4. (Standard) Find the average kinetic energy of a gas molecule at 342 K.
  5. (Challenge) By what factor does the rms speed change if the absolute temperature becomes 16 times?
  6. (Challenge) By what factor does the rms speed change if the absolute temperature becomes 4 times?

Answer key with full working

  • Q1: v = √(3 × 8.314 × 506 / 0.002) → = 2512.04 m/s → Answer: 2512.04 m/s
  • Q2: v = √(3 × 8.314 × 323 / 0.044) → = 427.9 m/s → Answer: 427.9 m/s
  • Q3: KE = (3/2)kT = 1.5 × 1.38 × 10⁻²³ × 267 → = 5.527e-21 J → Answer: 5.527e-21 J
  • Q4: KE = (3/2)kT = 1.5 × 1.38 × 10⁻²³ × 342 → = 7.079e-21 J → Answer: 7.079e-21 J
  • Q5: v ∝ √T → √16 = 4 → Answer: 4 times
  • Q6: v ∝ √T → √4 = 2 → Answer: 2 times

Syllabus note

This skill is listed under "Kinetic Theory" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is rms speed of gas molecules in?

"Kinetic Theory", Class 11 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Book a free demo class