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Magnetic force and circular paths: Class 12 practice

F = qvB sin θ on a moving charge and F = BIL sin θ on a current. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Circular motion

The idea behind magnetic force and circular paths

F = qvB sin θ on a moving charge and F = BIL sin θ on a current. A charge moving perpendicular to B goes in a circle of radius r = mv/(qB) with period T = 2πm/(qB).

Step-by-step method

  1. Find the angle between v (or I) and B.
  2. Use F = qvB sin θ or BIL sin θ.
  3. For circles: r = mv/qB.

Worked example 1 (Basic)

A 0.9 m wire carrying 9 A is at 90° to a 0.1 T field. Find the force.

  1. F = BIL sin θ
  2. = 0.81 N
  3. Answer: 0.81 N

Worked example 2 (Standard)

An electron moves at 5e+6 m/s perpendicular to a 3 mT field. Find the radius of its path.

  1. r = mv/qB
  2. = 9.479e-3 m
  3. Answer: 9.479e-3 m

Worked example 3 (Challenge)

Find the period of an electron circling in a 3 mT field.

  1. T = 2πm/qB
  2. = 1.191e-8 s (independent of speed)
  3. Answer: 1.191e-8 s

Common mistakes and misconceptions

  • Forgetting sin θ
  • Thinking the magnetic force changes speed

Practice questions

  1. (Basic) A 0.1 m wire carrying 2 A is at 90° to a 0.4 T field. Find the force.
  2. (Basic) A 0.3 m wire carrying 2 A is at 30° to a 0.3 T field. Find the force.
  3. (Standard) An electron moves at 2e+6 m/s perpendicular to a 2 mT field. Find the radius of its path.
  4. (Standard) An electron moves at 6e+6 m/s perpendicular to a 6 mT field. Find the radius of its path.
  5. (Challenge) Find the period of an electron circling in a 6 mT field.
  6. (Challenge) Find the period of an electron circling in a 5 mT field.

Answer key with full working

  • Q1: F = BIL sin θ → = 0.08 N → Answer: 0.08 N
  • Q2: F = BIL sin θ → = 0.09 N → Answer: 0.09 N
  • Q3: r = mv/qB → = 5.687e-3 m → Answer: 5.687e-3 m
  • Q4: r = mv/qB → = 5.687e-3 m → Answer: 5.687e-3 m
  • Q5: T = 2πm/qB → = 5.956e-9 s (independent of speed) → Answer: 5.956e-9 s
  • Q6: T = 2πm/qB → = 7.147e-9 s (independent of speed) → Answer: 7.147e-9 s

Syllabus note

This skill is listed under "Moving Charges and Magnetism" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is magnetic force and circular paths in?

"Moving Charges and Magnetism", Class 12 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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