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Spin-only magnetic moment: Class 12 practice

μ = √(n(n + 2)) BM, where n is the number of unpaired d electrons. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Electronic configuration

The idea behind spin-only magnetic moment

μ = √(n(n + 2)) BM, where n is the number of unpaired d electrons. Find the ion's d-electron count (group number minus charge for the 3d series), then fill orbitals by Hund's rule.

Step-by-step method

  1. Write the d-electron count of the ion.
  2. Place electrons singly first (Hund's rule), count unpaired.
  3. μ = √(n(n + 2)).

Worked example 1 (Basic)

Find the spin-only magnetic moment of Co²⁺.

  1. d-electrons: 7
  2. Unpaired: 3
  3. μ = √(3 × 5) = 3.87 BM
  4. Answer: 3.87 BM

Worked example 2 (Standard)

Find the spin-only magnetic moment of Sc³⁺.

  1. d-electrons: 0
  2. Unpaired: 0
  3. μ = √(0 × 2) = 0 BM
  4. Answer: 0 BM

Worked example 3 (Challenge)

Find the spin-only magnetic moment of Fe²⁺.

  1. d-electrons: 6
  2. Unpaired: 4
  3. μ = √(4 × 6) = 4.9 BM
  4. Answer: 4.9 BM

Common mistakes and misconceptions

  • Removing 3d electrons before 4s
  • Counting paired electrons

Practice questions

  1. (Basic) Find the spin-only magnetic moment of Cr³⁺.
  2. (Basic) Find the spin-only magnetic moment of Mn²⁺.
  3. (Standard) Find the spin-only magnetic moment of Ti³⁺.
  4. (Standard) Find the spin-only magnetic moment of Zn²⁺.
  5. (Challenge) Find the spin-only magnetic moment of Fe³⁺.
  6. (Challenge) Find the spin-only magnetic moment of Cr²⁺.

Answer key with full working

  • Q1: d-electrons: 3 → Unpaired: 3 → μ = √(3 × 5) = 3.87 BM → Answer: 3.87 BM
  • Q2: d-electrons: 5 → Unpaired: 5 → μ = √(5 × 7) = 5.92 BM → Answer: 5.92 BM
  • Q3: d-electrons: 1 → Unpaired: 1 → μ = √(1 × 3) = 1.73 BM → Answer: 1.73 BM
  • Q4: d-electrons: 10 → Unpaired: 0 → μ = √(0 × 2) = 0 BM → Answer: 0 BM
  • Q5: d-electrons: 5 → Unpaired: 5 → μ = √(5 × 7) = 5.92 BM → Answer: 5.92 BM
  • Q6: d-electrons: 4 → Unpaired: 4 → μ = √(4 × 6) = 4.9 BM → Answer: 4.9 BM

Syllabus note

This skill is listed under "d and f Block Elements" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is spin-only magnetic moment in?

"d and f Block Elements", Class 12 Chemistry (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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