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Product and quotient rules: Class 11 practice

(uv)′ = u′v + uv′ and (u/v)′ = (u′v − uv′)/v². Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Power rule

The idea behind product and quotient rules

(uv)′ = u′v + uv′ and (u/v)′ = (u′v − uv′)/v². Identify u and v, differentiate each, then substitute into the rule.

Step-by-step method

  1. Name u and v.
  2. Find u′ and v′.
  3. Apply the rule and simplify.
  4. Substitute a value if asked.

Worked example 1 (Basic)

If y = (1x − 5)(2x² + 1), find dy/dx at x = 2.

  1. u′ = 1, v′ = 4x
  2. dy/dx = 1(2x² + 1) + (1x − 5)(4x)
  3. At x = 2: -15
  4. Answer: -15

Worked example 2 (Standard)

If y = (3x − 4)(4x² + 1), find dy/dx at x = -3.

  1. u′ = 3, v′ = 8x
  2. dy/dx = 3(4x² + 1) + (3x − 4)(8x)
  3. At x = -3: 423
  4. Answer: 423

Worked example 3 (Challenge)

If y = (4x − 5)/(x² + 1), find dy/dx at x = 2.

  1. (u′v − uv′)/v²
  2. = [4(x² + 1) − (4x − 5)(2x)]/(x² + 1)²
  3. At x = 2: 8/25
  4. Answer: 8/25

Common mistakes and misconceptions

  • Writing (uv)′ = u′v′
  • Reversing the order in the quotient rule numerator

Practice questions

  1. (Basic) If y = (4x − 1)(2x² + 1), find dy/dx at x = -1.
  2. (Basic) If y = (3x − 5)(3x² + 1), find dy/dx at x = 3.
  3. (Standard) If y = (2x − 4)(1x² + 1), find dy/dx at x = -3.
  4. (Standard) If y = (5x − 4)(3x² + 1), find dy/dx at x = -3.
  5. (Challenge) If y = (2x + 1)/(x² + 4), find dy/dx at x = -2.
  6. (Challenge) If y = (1x + 2)/(x² + 4), find dy/dx at x = -3.

Answer key with full working

  • Q1: u′ = 4, v′ = 4x → dy/dx = 4(2x² + 1) + (4x − 1)(4x) → At x = -1: 32 → Answer: 32
  • Q2: u′ = 3, v′ = 6x → dy/dx = 3(3x² + 1) + (3x − 5)(6x) → At x = 3: 156 → Answer: 156
  • Q3: u′ = 2, v′ = 2x → dy/dx = 2(1x² + 1) + (2x − 4)(2x) → At x = -3: 80 → Answer: 80
  • Q4: u′ = 5, v′ = 6x → dy/dx = 5(3x² + 1) + (5x − 4)(6x) → At x = -3: 482 → Answer: 482
  • Q5: (u′v − uv′)/v² → = [2(x² + 4) − (2x + 1)(2x)]/(x² + 4)² → At x = -2: 1/16 → Answer: 1/16
  • Q6: (u′v − uv′)/v² → = [1(x² + 4) − (1x + 2)(2x)]/(x² + 4)² → At x = -3: 7/169 → Answer: 7/169

Syllabus note

This skill is listed under "Limits and Derivatives" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is product and quotient rules in?

"Limits and Derivatives", Class 11 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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