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Selections and committees: Class 11 practice

Use combinations when order doesn't matter: ⁿCᵣ = n!/(r!(n − r)!). Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Factorials
  • ⁿCᵣ

The idea behind selections and committees

Use combinations when order doesn't matter: ⁿCᵣ = n!/(r!(n − r)!). For mixed groups, multiply the choices for each part. 'At least' problems add cases or use total minus unwanted.

Step-by-step method

  1. Decide that order doesn't matter.
  2. Split into parts (e.g. men and women).
  3. Multiply combinations for each part; add separate cases.

Worked example 1 (Basic)

In how many ways can 2 students be chosen from 6?

  1. 6C2 = 15
  2. Answer: 15

Worked example 2 (Standard)

A committee of 3 men and 1 women is chosen from 8 men and 4 women. How many ways?

  1. 8C3 × 4C1 = 56 × 4
  2. = 224
  3. Answer: 224

Worked example 3 (Challenge)

A team of 3 is chosen from 7 men and 5 women. In how many ways does it include at least one man?

  1. Total 12C3 = 220
  2. All women 5C3 = 10
  3. At least one man = 210
  4. Answer: 210

Common mistakes and misconceptions

  • Using permutations
  • Adding where you should multiply

Practice questions

  1. (Basic) In how many ways can 2 students be chosen from 12?
  2. (Basic) In how many ways can 2 students be chosen from 11?
  3. (Standard) A committee of 1 men and 3 women is chosen from 7 men and 7 women. How many ways?
  4. (Standard) A committee of 2 men and 3 women is chosen from 7 men and 6 women. How many ways?
  5. (Challenge) A team of 3 is chosen from 8 men and 6 women. In how many ways does it include at least one man?
  6. (Challenge) A team of 3 is chosen from 8 men and 8 women. In how many ways does it include at least one man?

Answer key with full working

  • Q1: 12C2 = 66 → Answer: 66
  • Q2: 11C2 = 55 → Answer: 55
  • Q3: 7C1 × 7C3 = 7 × 35 → = 245 → Answer: 245
  • Q4: 7C2 × 6C3 = 21 × 20 → = 420 → Answer: 420
  • Q5: Total 14C3 = 364 → All women 6C3 = 20 → At least one man = 344 → Answer: 344
  • Q6: Total 16C3 = 560 → All women 8C3 = 56 → At least one man = 504 → Answer: 504

Syllabus note

This skill is listed under "Permutations and Combinations" for Class 11 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is selections and committees in?

"Permutations and Combinations", Class 11 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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