RG's E-Learning Centre · Book a free demo class · WhatsApp +91-9379416374

Solving quadratic equations: Class 10 practice

A quadratic ax² + bx + c = 0 has roots x = [−b ± √(b² − 4ac)] / 2a. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Factorising
  • Square roots

The idea behind solving quadratic equations

A quadratic ax² + bx + c = 0 has roots x = [−b ± √(b² − 4ac)] / 2a. The discriminant D = b² − 4ac tells you the nature of the roots: D > 0 two real roots, D = 0 equal roots, D < 0 no real roots.

Step-by-step method

  1. Write in standard form.
  2. Compute D = b² − 4ac.
  3. Factorise by splitting the middle term, or use the formula.
  4. Check by substitution.

Worked example 1 (Basic)

Solve x² − 12x + 35 = 0.

  1. D = (-12)² − 4(1)(35) = 4
  2. Factorise: (x − 5)(x − 7) = 0
  3. x = 5 or x = 7
  4. Answer: x = 5, 7

Worked example 2 (Standard)

Solve x² − 8x + 7 = 0.

  1. D = (-8)² − 4(1)(7) = 36
  2. Factorise: (x − 1)(x − 7) = 0
  3. x = 1 or x = 7
  4. Answer: x = 1, 7

Worked example 3 (Challenge)

Solve 3x² + 20x + 12 = 0.

  1. D = (20)² − 4(3)(12) = 256
  2. Factorise: (3x + 2)(x + 6) = 0
  3. x = -2/3 or x = -6
  4. Answer: x = -2/3, -6

Common mistakes and misconceptions

  • Sign error in −b
  • Dividing only √D by 2a

Practice questions

  1. (Basic) Solve x² − 5x − 6 = 0.
  2. (Basic) Solve x² − 5x + 4 = 0.
  3. (Standard) Solve x² − 8x + 15 = 0.
  4. (Standard) Solve x² + 2x − 15 = 0.
  5. (Challenge) Solve 2x² − 11x + 5 = 0.
  6. (Challenge) Solve 2x² − 9x − 35 = 0.

Answer key with full working

  • Q1: D = (-5)² − 4(1)(-6) = 49 → Factorise: (x + 1)(x − 6) = 0 → x = -1 or x = 6 → Answer: x = -1, 6
  • Q2: D = (-5)² − 4(1)(4) = 9 → Factorise: (x − 1)(x − 4) = 0 → x = 1 or x = 4 → Answer: x = 1, 4
  • Q3: D = (-8)² − 4(1)(15) = 4 → Factorise: (x − 5)(x − 3) = 0 → x = 5 or x = 3 → Answer: x = 5, 3
  • Q4: D = (2)² − 4(1)(-15) = 64 → Factorise: (x − 3)(x + 5) = 0 → x = 3 or x = -5 → Answer: x = 3, -5
  • Q5: D = (-11)² − 4(2)(5) = 81 → Factorise: (2x − 1)(x − 5) = 0 → x = 1/2 or x = 5 → Answer: x = 1/2, 5
  • Q6: D = (-9)² − 4(2)(-35) = 361 → Factorise: (2x + 5)(x − 7) = 0 → x = -5/2 or x = 7 → Answer: x = -5/2, 7

Syllabus note

This skill is listed under "Quadratic Equations" for Class 10 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is solving quadratic equations in?

"Quadratic Equations", Class 10 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Book a free demo class