RG's E-Learning Centre · Book a free demo class · WhatsApp +91-9379416374

Chain rule: Class 12 practice

To differentiate a function of a function, differentiate the outside (keeping the inside) and multiply by the derivative of the inside: d/dx f(g(x)) = f′(g(x)) g′(x).. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Standard derivatives

The idea behind chain rule

To differentiate a function of a function, differentiate the outside (keeping the inside) and multiply by the derivative of the inside: d/dx f(g(x)) = f′(g(x)) g′(x).

Step-by-step method

  1. Spot the inner function.
  2. Differentiate the outer function.
  3. Multiply by the inner derivative.
  4. Simplify.

Worked example 1 (Basic)

Find dy/dx at x = 0 for y = (3x + 4)^4.

  1. dy/dx = 4(3x + 4)^3 × 3
  2. At x = 0: 768
  3. Answer: 768

Worked example 2 (Standard)

Differentiate y = sin(5x² + 2).

  1. Outer: cos(…), inner derivative 10x
  2. Answer: 10x cos(5x² + 2)

Worked example 3 (Challenge)

Differentiate y = e^(6x + 3) and find dy/dx at x = 0.

  1. dy/dx = 6e^(6x + 3)
  2. At 0: 6e^3 ≈ 120.5132
  3. Answer: 6e^(6x + 3); at 0 ≈ 120.5132

Common mistakes and misconceptions

  • Forgetting the inner derivative
  • Differentiating the inside twice

Practice questions

  1. (Basic) Find dy/dx at x = 1 for y = (4x + 2)^5.
  2. (Basic) Find dy/dx at x = 1 for y = (3x − 5)^5.
  3. (Standard) Differentiate y = sin(6x² − 5).
  4. (Standard) Differentiate y = sin(3x² + 2).
  5. (Challenge) Differentiate y = e^(4x − 2) and find dy/dx at x = 0.
  6. (Challenge) Differentiate y = e^(6x − 4) and find dy/dx at x = 0.

Answer key with full working

  • Q1: dy/dx = 5(4x + 2)^4 × 4 → At x = 1: 25920 → Answer: 25920
  • Q2: dy/dx = 5(3x − 5)^4 × 3 → At x = 1: 240 → Answer: 240
  • Q3: Outer: cos(…), inner derivative 12x → Answer: 12x cos(6x² − 5)
  • Q4: Outer: cos(…), inner derivative 6x → Answer: 6x cos(3x² + 2)
  • Q5: dy/dx = 4e^(4x − 2) → At 0: 4e^-2 ≈ 0.5413 → Answer: 4e^(4x − 2); at 0 ≈ 0.5413
  • Q6: dy/dx = 6e^(6x − 4) → At 0: 6e^-4 ≈ 0.1099 → Answer: 6e^(6x − 4); at 0 ≈ 0.1099

Syllabus note

This skill is listed under "Continuity and Differentiability" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is chain rule in?

"Continuity and Differentiability", Class 12 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Book a free demo class