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Derivatives of polynomials and slope of a tangent: Class 12 practice

The derivative f′(x) gives the slope of the tangent to y = f(x). Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Laws of exponents
  • Straight-line equation

The idea behind derivatives of polynomials and slope of a tangent

The derivative f′(x) gives the slope of the tangent to y = f(x). For powers, d/dx(xⁿ) = nxⁿ⁻¹, and derivatives of sums are sums of derivatives.

Step-by-step method

  1. Differentiate term by term with the power rule.
  2. Substitute the x-value for the slope.
  3. Tangent line: y − y₀ = f′(x₀)(x − x₀).

Worked example 1 (Basic)

If f(x) = 3x³ + 1x² + 0x + 2, find f′(-3).

  1. f′(x) = 9x² + 2x + 0
  2. f′(-3) = 75
  3. Answer: 75

Worked example 2 (Standard)

If f(x) = 1x³ + 0x² − 3x + 9, find f′(1).

  1. f′(x) = 3x² + 0x − 3
  2. f′(1) = 0
  3. Answer: 0

Worked example 3 (Challenge)

Find the equation of the tangent to y = 4x³ + 3x² − 8x − 1 at x = 3.

  1. y′ = 12x² + 6x − 8
  2. Slope at x = 3: 118
  3. Point: (3, 110)
  4. y − 110 = 118(x − 3)
  5. Answer: y = 118x − 244

Common mistakes and misconceptions

  • Forgetting that a constant's derivative is 0
  • Substituting before differentiating

Practice questions

  1. (Basic) If f(x) = 2x³ − 2x² + 8x − 9, find f′(-3).
  2. (Basic) If f(x) = 3x³ + 2x² − 3x + 0, find f′(0).
  3. (Standard) If f(x) = 1x³ + 0x² + 8x − 9, find f′(2).
  4. (Standard) If f(x) = 4x³ − 6x² − 8x + 9, find f′(-1).
  5. (Challenge) Find the equation of the tangent to y = 4x³ − 1x² − 2x + 5 at x = 2.
  6. (Challenge) Find the equation of the tangent to y = 1x³ − 5x² + 7x − 4 at x = -1.

Answer key with full working

  • Q1: f′(x) = 6x² − 4x + 8 → f′(-3) = 74 → Answer: 74
  • Q2: f′(x) = 9x² + 4x − 3 → f′(0) = -3 → Answer: -3
  • Q3: f′(x) = 3x² + 0x + 8 → f′(2) = 20 → Answer: 20
  • Q4: f′(x) = 12x² − 12x − 8 → f′(-1) = 16 → Answer: 16
  • Q5: y′ = 12x² − 2x − 2 → Slope at x = 2: 42 → Point: (2, 29) → y − 29 = 42(x − 2) → Answer: y = 42x − 55
  • Q6: y′ = 3x² − 10x + 7 → Slope at x = -1: 20 → Point: (-1, -17) → y − -17 = 20(x − -1) → Answer: y = 20x + 3

Syllabus note

This skill is listed under "Continuity and Differentiability" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is derivatives of polynomials and slope of a tangent in?

"Continuity and Differentiability", Class 12 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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