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Dot product, angle and cross product: Class 12 practice

a·b = a₁b₁ + a₂b₂ + a₃b₃ = |a||b| cos θ. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Magnitude of a vector

The idea behind dot product, angle and cross product

a·b = a₁b₁ + a₂b₂ + a₃b₃ = |a||b| cos θ. a × b is perpendicular to both, with |a × b| = |a||b| sin θ = area of the parallelogram on a and b.

Step-by-step method

  1. Compute a·b component-wise.
  2. cos θ = a·b ÷ (|a||b|).
  3. For a × b use the determinant with i, j, k.

Worked example 1 (Basic)

Find a·b for a = 1i − 3j − 1k and b = 3i + 4j − 1k.

  1. 1×3 + -3×4 + -1×-1
  2. = -8
  3. Answer: -8

Worked example 2 (Standard)

Find a × b for a = 0i − 3j − 2k and b = -4i − 1j + 4k.

  1. i(-3·4 − -2·-1) − j(0·4 − -2·-4) + k(0·-1 − -3·-4)
  2. = -14i + 8j − 12k
  3. Answer: -14i + 8j − 12k

Worked example 3 (Challenge)

Find the area of the parallelogram with adjacent sides a = -3i − 2j + 3k and b = -1i − 4j − 1k.

  1. a × b = 14i − 6j + 10k
  2. Area = |a × b| = √332
  3. Answer: √332

Common mistakes and misconceptions

  • Adding components for a·b
  • Wrong sign on the j component of a × b

Practice questions

  1. (Basic) Find a·b for a = 4i − 2j + 4k and b = -4i + 1j − 3k.
  2. (Basic) Find a·b for a = 1i − 2j − 4k and b = -1i + 3j − 3k.
  3. (Standard) Find a × b for a = -4i − 3j − 3k and b = 3i − 4j − 2k.
  4. (Standard) Find a × b for a = 1i − 3j + 4k and b = 1i − 2j + 1k.
  5. (Challenge) Find the area of the parallelogram with adjacent sides a = -1i + 1j − 4k and b = 1i + 2j + 1k.
  6. (Challenge) Find the area of the parallelogram with adjacent sides a = -1i + 2j + 3k and b = 0i + 3j + 2k.

Answer key with full working

  • Q1: 4×-4 + -2×1 + 4×-3 → = -30 → Answer: -30
  • Q2: 1×-1 + -2×3 + -4×-3 → = 5 → Answer: 5
  • Q3: i(-3·-2 − -3·-4) − j(-4·-2 − -3·3) + k(-4·-4 − -3·3) → = -6i − 17j + 25k → Answer: -6i − 17j + 25k
  • Q4: i(-3·1 − 4·-2) − j(1·1 − 4·1) + k(1·-2 − -3·1) → = 5i + 3j + 1k → Answer: 5i + 3j + 1k
  • Q5: a × b = 9i − 3j − 3k → Area = |a × b| = √99 → Answer: √99
  • Q6: a × b = -5i + 2j − 3k → Area = |a × b| = √38 → Answer: √38

Syllabus note

This skill is listed under "Vector Algebra" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is dot product, angle and cross product in?

"Vector Algebra", Class 12 Maths (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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