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Echoes and SONAR: Class 9 practice

An echo travels to the reflector and back, so distance = speed × time ÷ 2. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Speed = distance/time

The idea behind echoes and sonar

An echo travels to the reflector and back, so distance = speed × time ÷ 2. A clear echo needs at least 0.1 s delay, so the reflector must be at least about 17 m away in air (v ≈ 344 m/s).

Step-by-step method

  1. Total path = v × t.
  2. Distance to the reflector = half of that.
  3. Use 1500 m/s in sea water for SONAR.

Worked example 1 (Basic)

A shout returns after 3 s (speed 340 m/s). How far is the cliff?

  1. d = 340 × 3 ÷ 2
  2. Answer: 510 m

Worked example 2 (Standard)

A ship's SONAR signal returns after 2 s (speed 1500 m/s). How far is the sea bed?

  1. d = 1500 × 2 ÷ 2
  2. Answer: 1500 m

Worked example 3 (Challenge)

What is the minimum distance from a wall for a clear echo if sound travels at 340 m/s?

  1. Echo needs 0.1 s
  2. d = 340 × 0.1/2 = 17 m
  3. Answer: 17 m

Common mistakes and misconceptions

  • Forgetting to halve
  • Using the speed of light

Practice questions

  1. (Basic) A shout returns after 3 s (speed 344 m/s). How far is the cliff?
  2. (Basic) A shout returns after 5.5 s (speed 344 m/s). How far is the cliff?
  3. (Standard) A ship's SONAR signal returns after 6 s (speed 1500 m/s). How far is the sea bed?
  4. (Standard) A ship's SONAR signal returns after 4 s (speed 1500 m/s). How far is the sea bed?
  5. (Challenge) What is the minimum distance from a wall for a clear echo if sound travels at 330 m/s?
  6. (Challenge) What is the minimum distance from a wall for a clear echo if sound travels at 344 m/s?

Answer key with full working

  • Q1: d = 344 × 3 ÷ 2 → Answer: 516 m
  • Q2: d = 344 × 5.5 ÷ 2 → Answer: 946 m
  • Q3: d = 1500 × 6 ÷ 2 → Answer: 4500 m
  • Q4: d = 1500 × 4 ÷ 2 → Answer: 3000 m
  • Q5: Echo needs 0.1 s → d = 330 × 0.1/2 = 16.5 m → Answer: 16.5 m
  • Q6: Echo needs 0.1 s → d = 344 × 0.1/2 = 17.2 m → Answer: 17.2 m

Syllabus note

This skill is listed under "Sound" for Class 9 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is echoes and sonar in?

"Sound", Class 9 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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