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Frequency, time period and audible range: Class 9 practice

Frequency is the number of oscillations per second (Hz) and time period T = 1/f. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Fractions
  • Units

The idea behind frequency, time period and audible range

Frequency is the number of oscillations per second (Hz) and time period T = 1/f. Humans hear about 20 Hz to 20 kHz; lower is infrasound, higher is ultrasound.

Step-by-step method

  1. T = 1/f or f = 1/T.
  2. Compare f with 20 Hz and 20 000 Hz.

Worked example 1 (Basic)

A source vibrates at 15000 Hz. Find its time period.

  1. T = 1/15000 = 6.67e-5 s
  2. Answer: 6.67e-5 s

Worked example 2 (Standard)

A source vibrates at 5 Hz. Find its time period and say whether it is audible.

  1. T = 1/5 = 2.00e-1 s
  2. infrasound
  3. Answer: 2.00e-1 s, infrasound

Worked example 3 (Challenge)

A wave has time period 0.002 s. Find its frequency and say whether humans can hear it.

  1. f = 1/0.002 = 500 Hz
  2. Audible
  3. Answer: 500 Hz, audible

Common mistakes and misconceptions

  • Mixing kHz and Hz
  • Calling 15 Hz ultrasound

Practice questions

  1. (Basic) A source vibrates at 256 Hz. Find its time period.
  2. (Basic) A source vibrates at 25000 Hz. Find its time period.
  3. (Standard) A source vibrates at 12 Hz. Find its time period and say whether it is audible.
  4. (Standard) A source vibrates at 40000 Hz. Find its time period and say whether it is audible.
  5. (Challenge) A wave has time period 0.00004 s. Find its frequency and say whether humans can hear it.
  6. (Challenge) A wave has time period 0.01 s. Find its frequency and say whether humans can hear it.

Answer key with full working

  • Q1: T = 1/256 = 3.91e-3 s → Answer: 3.91e-3 s
  • Q2: T = 1/25000 = 4.00e-5 s → Answer: 4.00e-5 s
  • Q3: T = 1/12 = 8.33e-2 s → infrasound → Answer: 8.33e-2 s, infrasound
  • Q4: T = 1/40000 = 2.50e-5 s → ultrasound → Answer: 2.50e-5 s, ultrasound
  • Q5: f = 1/0.00004 = 25000 Hz → Above 20 kHz → ultrasound → Answer: 25000 Hz, ultrasound
  • Q6: f = 1/0.01 = 100 Hz → Audible → Answer: 100 Hz, audible

Syllabus note

This skill is listed under "Sound" for Class 9 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is frequency, time period and audible range in?

"Sound", Class 9 Physics (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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