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Osmotic pressure: Class 12 practice

π = CRT = (n/V)RT. Read the method, follow the three worked examples, then try the six questions.

What you should know first

  • Molarity

The idea behind osmotic pressure

π = CRT = (n/V)RT. Measuring π gives the molar mass of a solute: M = wRT/(πV). Use R = 0.0821 L atm mol⁻¹ K⁻¹, V in litres and T in K.

Step-by-step method

  1. Convert volume to L and temperature to K.
  2. π = (w/M)RT/V.
  3. Rearrange for the unknown.

Worked example 1 (Basic)

6 g of a solute (M = 342 g/mol) is dissolved to make 100 mL at 285 K. Find the osmotic pressure.

  1. C = 6/342/0.1
  2. π = CRT = 4.105 atm
  3. Answer: 4.105 atm

Worked example 2 (Standard)

13 g of a solute (M = 20000 g/mol) is dissolved to make 1000 mL at 286 K. Find the osmotic pressure.

  1. C = 13/20000/1
  2. π = CRT = 0.01526 atm
  3. Answer: 0.01526 atm

Worked example 3 (Challenge)

19 g of a protein in 500 mL gives π = 5.477 atm at 316 K. Find its molar mass.

  1. M = wRT/(πV)
  2. Answer: 180 g/mol

Common mistakes and misconceptions

  • Using mL
  • Using °C

Practice questions

  1. (Basic) 4 g of a solute (M = 60 g/mol) is dissolved to make 250 mL at 300 K. Find the osmotic pressure.
  2. (Basic) 16 g of a solute (M = 342 g/mol) is dissolved to make 500 mL at 280 K. Find the osmotic pressure.
  3. (Standard) 18 g of a solute (M = 60 g/mol) is dissolved to make 250 mL at 309 K. Find the osmotic pressure.
  4. (Standard) 2 g of a solute (M = 5000 g/mol) is dissolved to make 250 mL at 316 K. Find the osmotic pressure.
  5. (Challenge) 20 g of a protein in 250 mL gives π = 10.40 atm at 285 K. Find its molar mass.
  6. (Challenge) 11 g of a protein in 100 mL gives π = 0.5202 atm at 288 K. Find its molar mass.

Answer key with full working

  • Q1: C = 4/60/0.25 → π = CRT = 6.568 atm → Answer: 6.568 atm
  • Q2: C = 16/342/0.5 → π = CRT = 2.151 atm → Answer: 2.151 atm
  • Q3: C = 18/60/0.25 → π = CRT = 30.44 atm → Answer: 30.44 atm
  • Q4: C = 2/5000/0.25 → π = CRT = 0.04151 atm → Answer: 0.04151 atm
  • Q5: M = wRT/(πV) → Answer: 180 g/mol
  • Q6: M = wRT/(πV) → Answer: 5000 g/mol

Syllabus note

This skill is listed under "Solutions" for Class 12 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

Related practice and notes

Frequently asked questions

Which chapter is osmotic pressure in?

"Solutions", Class 12 Chemistry (NCERT/CBSE). Other boards may place it differently.

How were the answers checked?

Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.

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