Median of grouped data: Class 10 practice
Find n/2, locate the median class using cumulative frequency, then Median = l + [(n/2 − cf)/f] × h, where cf is the cumulative frequency before the median class.. Read the method, follow the three worked examples, then try the six questions.
What you should know first
- Cumulative frequency
The idea behind median of grouped data
Find n/2, locate the median class using cumulative frequency, then Median = l + [(n/2 − cf)/f] × h, where cf is the cumulative frequency before the median class.
Step-by-step method
- Build the cumulative frequency column.
- Find n/2 and the class containing it.
- Substitute l, cf, f, h.
Worked example 1 (Basic)
Find the median: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 6, 5, 10, 6, 3.
- n = 30, n/2 = 15
- Cumulative: 6, 11, 21, 27, 30 → median class 20–30
- Median = 20 + ((15 − 11)/10) × 10 = 24.00
- Answer: 24.00
Worked example 2 (Standard)
Find the median: classes 20–30, 30–40, 40–50, 50–60, 60–70 with frequencies 10, 9, 4, 10, 4.
- n = 37, n/2 = 18.5
- Cumulative: 10, 19, 23, 33, 37 → median class 30–40
- Median = 30 + ((18.5 − 10)/9) × 10 = 39.44
- Answer: 39.44
Worked example 3 (Challenge)
Find the median: classes 20–30, 30–40, 40–50, 50–60, 60–70 with frequencies 7, 12, 6, 6, 6.
- n = 37, n/2 = 18.5
- Cumulative: 7, 19, 25, 31, 37 → median class 30–40
- Median = 30 + ((18.5 − 7)/12) × 10 = 39.58
- Answer: 39.58
Common mistakes and misconceptions
- Using the median class's own cf
- Using n instead of n/2
Practice questions
- (Basic) Find the median: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 8, 6, 12, 6, 8.
- (Basic) Find the median: classes 20–30, 30–40, 40–50, 50–60, 60–70 with frequencies 11, 5, 6, 3, 4.
- (Standard) Find the median: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 3, 10, 10, 7, 10.
- (Standard) Find the median: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 5, 5, 7, 9, 11.
- (Challenge) Find the median: classes 10–20, 20–30, 30–40, 40–50, 50–60 with frequencies 10, 10, 9, 9, 6.
- (Challenge) Find the median: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 12, 7, 10, 12, 9.
Answer key with full working
- Q1: n = 40, n/2 = 20 → Cumulative: 8, 14, 26, 32, 40 → median class 20–30 → Median = 20 + ((20 − 14)/12) × 10 = 25.00 → Answer: 25.00
- Q2: n = 29, n/2 = 14.5 → Cumulative: 11, 16, 22, 25, 29 → median class 30–40 → Median = 30 + ((14.5 − 11)/5) × 10 = 37.00 → Answer: 37.00
- Q3: n = 40, n/2 = 20 → Cumulative: 3, 13, 23, 30, 40 → median class 20–30 → Median = 20 + ((20 − 13)/10) × 10 = 27.00 → Answer: 27.00
- Q4: n = 37, n/2 = 18.5 → Cumulative: 5, 10, 17, 26, 37 → median class 30–40 → Median = 30 + ((18.5 − 17)/9) × 10 = 31.67 → Answer: 31.67
- Q5: n = 44, n/2 = 22 → Cumulative: 10, 20, 29, 38, 44 → median class 30–40 → Median = 30 + ((22 − 20)/9) × 10 = 32.22 → Answer: 32.22
- Q6: n = 50, n/2 = 25 → Cumulative: 12, 19, 29, 41, 50 → median class 20–30 → Median = 20 + ((25 − 19)/10) × 10 = 26.00 → Answer: 26.00
Syllabus note
This skill is listed under "Statistics" for Class 10 in the NCERT/CBSE books. ICSE, IGCSE, IB and state boards may teach it in a different chapter or year.
Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.
Related practice and notes
Frequently asked questions
Which chapter is median of grouped data in?
"Statistics", Class 10 Maths (NCERT/CBSE). Other boards may place it differently.
How were the answers checked?
Answers on this page are generated and automatically re-checked by a second, independent calculation. They have not been reviewed by a teacher — if you spot a problem, tell us on WhatsApp.